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The molecular kinetic energy of 1 g of helium (molecular weight 4) at `127^(@)C` is (Given , R `=8.31 J"mol"^(-1)K^(-1)` )A. 12.84 JB. 12.465 JC. 14.34D. 14.384 J |
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Answer» Correct Answer - B Given , T = 273 + 127 = 400 K `because` Helium is monoatmic gas. `therefore` Average kinetic energy per mole of helium = `(3)/(2)RT` Average kinetic energy of 1 g of helium = `(3)/(2)(RT)/(M)` `=(3xx8.31xx4.00)/(2xx4)=12.465J` |
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