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The molecules of a given mass of gas have a rms velocity of `200 m//sec at 127^(@)C and 1.0 xx 10^(5) N//m^(2)` pressure. When the temperature is `127^(@)C` and pressure is `0.5 xx 10^(5) N//m^(2)` the rms velocity in `m//sec` will beA. `(100sqrt(2))/(3)`B. `100sqrt(2)`C. `(400)/sqrt(3)`D. 400 |
Answer» Correct Answer - C `v_(rms)=sqrt((3RT)/(M))rArrv_(rms)propsqrt(T)` |
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