The moment of force of 30 N about an axix of rotation at distance 1.5 – InterviewSolution

1.	The moment of force of 30 N about an axix of rotation at distance 1.5 m =
Answer» 45 NmStep-by-step EXPLANATION:Torque or moment of force = force * PERPENDICULAR DISTANCE so torque = force * distance = 30*1.5 = 45

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