Saved Bookmarks
| 1. |
The moment of inertia of a body about a given axis is 1.2 kg m^(2). · Initially, the body is at rest. In order to produce a rotational kinetic energy of 1500 J, an angular acceleration of 25 rad/s^(2) must be applied about that axis for a duration of |
|
Answer» 4s `alpha=25` RAD/`s^(2),omega_(1)=0,t=?` As `E_(r)=1/2Iomega^(2)rArromega=sqrt((2E_(r))/l),` `rArromega=sqrt((2xx1500)/(1.2))=50` rad/s From `omega=omega_(0)+alphat` `50=0+25t`, or t=2s |
|