1.

The moment of inertia of a circular loop of radius R, at a distance of `R//2` around a rotating axis parallel to horizontal diameter of loop isA. `MR^(2)`B. `(1)/(2)MR^(2)`C. `2MR^(2)`D. `(3)/(4)MR^(2)`

Answer» Correct Answer - D
According to theorem of parallel axis,
`I=I_(CM)+M((R)/(2))^(2)`
`rArr I=(1)/(2)MR^(2)+(MR^(2))/(4)`
Moment of inertia, `I = (3)/(4) MR^(2)`.


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