1.

The moment of inertia of a solid sphere of density p and radius R about its diameter is

Answer»

`(176piR^(3))/105`
`(176pR^(5))/105`
`(105pR^(3))/176`
`(105pR^(5))/176`

Solution :For a sphere `I=2/5MR^(2)`
Mass = Volume `XX` Density.
`I=2/5(4/3piR^(3).p).R^(2)=8/15pipR^(5)=8/15xx22/7pR^(5)=176/105pR^(5)`


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