1.

The moment of inertia of a solid sphere of mass M and radius R, about an axis through its centre, is (2)/(5)MR^(2). The moment of inertia about an axis tangential to the surface of the sphere will be :

Answer»

`(4)/(5)MR^(2)`
`(6)/(5)MR^(2)`
`(7)/(5)MR^(2)`
`MR^(2)`

Solution :`I_(T)=I_(C)+MR^(2)=(2)/(5)MR^(2)+MR^(2)=(7)/(5)MR^(2)`


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