1.

The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

Answer»

`MR^(2)`
`1/2MR^(2)`
`3/2MR^(2)`
`7/2MR^(2)`

SOLUTION :M.I. of DISC about its normal `=1/2MR^(2)`
M.I. about its one edge =`MR^(2)+(MR^(2))/2`
(Perpendicular to the PLANE)
MOMENT of inertia =`3/2MR^(2)`.


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