1.

The moment of Inertia of a uniform semicircular disc of mass M and radius 'r' about a line perpendicular to the plane of the disc through the centre is :

Answer»

`(1)/(4)Mr^(2)`
`(2)/(5)Mr^(2)`
`Mr^(2)`
`(1)/(2)Mr^(2)`

SOLUTION :MI of full disc of double mass is `I=((1)/(2)2Mr^(2))=Mr^(2)`
implies MI of given half disc is `I.=(1)/(2)(Mr^(2))=(1)/(2)Mr^(2)`


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