1.

The moment of inertia of circular disc about its diameter is 200 g cm^(2). Then its moment of inertia about an axis passing through its centre and normal to its face is :

Answer»

`100gcm^(2)`
`200gcm^(2)`
`400gcm^(2)`
`1000gcm^(2)`

SOLUTION :By theorem of `_|_` AXIS
`I_(zz.)=I_(AB)+I_(CD)`
`I_(zz.)=21_(d)=400gcm^(2)`


Discussion

No Comment Found

Related InterviewSolutions