1.

The momentum of a body increases by 20%. What is the percentage increase in its K.E.?

Answer»

60
52
44
36

Solution :`p’=p+(20)/(100)p=(6)/(5)p`
When momentum BECOMES n times then % change in
`K.E. = (n^(2) - 1)xx100 = ((36)/(25) – 1)X100`
`=(11)/(25)xx100=44%`
HENCE correct choice is (c).


Discussion

No Comment Found

Related InterviewSolutions