1.

The momentum of a photon of an electromagnetic radiation is 3.3xx10^(-29) kg m/s. The frequcncy of the associated wave is (h=6.6xx10^(-34)Js,c=3xx10^(8)m//s)

Answer»

`3.0xx10^(3)HZ`
`6.0xx10^(3)Hz`
`7.5xx10^(12)Hz`
`1.5xx10^(13)Hz`.

Solution :We know that moment `p=mv=(h)/(lambda)`
`HV=(HC)/(lambda)pc, v=(pc)/(h)=(3.3xx10^(-29)xx3xx10^(8))/(6.6xx10^(-34))`
`=1.5xx10^(13)Hz`.


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