1.

The momentum of a photon of an electron-magnetic radiation is 6.6xx10^(-29)kgms^(-1). If h=6.6xx10^(-34) js and c=3xx10^(8) m/sthe frequency of the radiation is

Answer»

`3xx10^(12)Hz`
`1.5xx10^(13)Hz`
`3xx10^(13)Hz`
`1.5xx10^(12)Hz.`

Solution :SINCE `p=(HV)/(C)`
`v=(PC)/(h)=(6.6xx10^(-29)xx3xx10^(8))/(6.6xx10^(-34))`
`=3xx10^(13)Hz`


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