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The momentum of a photon of energy 1 MeV in kg-m/s, will beA. 0.33 × `10^(6)`B. ` 7 × 10^(–24)`C. `10^(–22)`D. ` 5× 10^(–22)` |
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Answer» Correct Answer - D For a photon E=pc `impliesp=(E)/(c)=(10^(6)xx1.6xx10^(-19))/(3xx10^(8))=5.33xx10^(-22)` `kgms^(-1)` |
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