1.

The momentum of a photon of energy 1 MeV is kg m/s will be

Answer»

<P>`5 xx 10^(-22)`
`0.33 xx 10^(6)`
`7 xx 10^(-24)`
`10^(-22)`

Solution :`P = (E)/(C) = (1 MeV)/(3 xx 10^(8) ms^(-1)) = (1.6 xx 10^(-13) J)/(3 xx 10^(8) ms^(-1)) = 5.33 xx 10^(-22) "kg ms"^(-1)`


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