1.

The momentum of body decreases by 20% The percentage decrease in kinetic energy of the body is :

Answer»

0.36
0.24
0.12
None of these

Solution :`p.=p-(20)/(100)p=4/5p`
When MOMENTUM becomes N times then % change in
`K.E=(n^(2)-1)xx100`
=`[(4/3)^(2)-1]xx100=((16)/(25)-1)xx100=-36%`
-ve SIGN show that ENERGY decreses by 36%.


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