InterviewSolution
Saved Bookmarks
| 1. |
The most common oxidation states of cerium areA. `+2` and `+3`B. `+3` and `+4`C. `+2` and `+4`D. `+3` and `+5` |
|
Answer» Correct Answer - B The formation of `Ce(+4)` is favoured by its noble gas configuration, but it is a strong oxidant reverting to the common `+3` state. Thus, ceric sulphate, `Ce(SO_(4))_(2)` is most widely used as an oxidizing agent in the volumetric analysis. On heating in oxygen, lanthanides burn easily to give `M_(2)O_(3)` xcept for cerium which form `CO_(2)` as `Ce_(2)O_(3)` is oxidized by `O_(2)` . |
|