1.

The motion of a particle is described by the equation `x = a+bt^(2)` where `a = 15` cm and `b = 3 cm//s`. Its instantaneous velocity at time 3 sec will beA. `33 cm s^(-1)`B. `18 cm s^(-1)`C. `16 cm s^(-1)`D. `32 cm s^(-1)`

Answer» Correct Answer - A
Here, x = `at + bt^(2)`
where a = `15 cm s^(-1)`, b = `3 cm s^(-2)`
Velocity, `v = dx/dt = d/dt(at + bt^(2)) = a + bt`
At t = 3 s, v = `15 + 2 xx 3 xx 3 = 33 cm s^(-1)`


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