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The motor of an engine is rotating about its axis with an angular velocity of 100 rpm. It comes to rest in 15 s after being switched off. Assuming constant angular deceleration, calculate the number of revolution made by it before coming to rest.A. `12.5`B. 40C. `32.6`D. `15.6` |
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Answer» Correct Answer - A From equation of motion (angular), `0=omega_(0)-alphatrArralpha=(omega_(0))/(t)=((100xx2pi)//60)/(15)=0.69"rad s"^(-2)` Now, angle rotated before coming to rest is given by `theta=(omega_(0)^(2))/(2alpha)=((100xx2pi)/(60))^(2)/(2xx0.7)=78.25rad` `therefore" Number of revolutions"=(theta)/(2pi)=12.5` |
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