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The motor of an engine is rotating about its axis with an angular velocity of 100 rpm. It comes to rest in 15 s after being switched off. Assuming constant angular deceleration, calculate the number of revolution made by it before coming to rest.A. 12.5B. 40C. 32.6D. 15.6 |
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Answer» Correct Answer - A From the equation, `0 = omega_(0) - alpha t` `:. alpha=(omega_(0))/(t)=((100xx2pi)//60)/(15)=0.7 "rad s"^(-2)` Now angle rotated before coming to rest, `theta = (omega_(0)^(2))/(2 alpha)` or `theta =((100xx2pi//60)^(2))/(2xx0.7)=78.33` rad or number rotations, `n=(theta)/(2pi)=12.5`. |
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