1.

The moving coil galvanometer has of 500 turns. The loop is 5xx10^3 and angle of twist 5 Nm. What will be the reduction factor it the magnetic field is 5xx10^(-4)(Wb)//m^2?

Answer»

`1.33xx10^(-4) Am^2`
`1.33xx10^(-5)Am^2`
`1.33xx10^(+4)Am^2`
`400 Am^2`

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