InterviewSolution
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InterviewSolution
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The multiplicative inverse of `A = [(cos theta,-sin theta),(sin theta,cos theta)]`isA. `[{:(-cos theta, sin theta),(-sin theta, -cos theta):}]`B. `[{:(cos theta, sin theta),(-sin theta, cos theta):}]`C. `[{:(-cos theta, -sin theta),(sin theta, -cos theta):}]`D. `[{:(cos theta, sin theta),(sin theta, -cos theta):}]` |
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Answer» Correct Answer - B `|A|=cos ^(2)+sin^(2)theta=1` `adj(A)=[{:(cos theta,sintheta),(-sin theta, cos theta):}]` `A^(-1)=(adj(A))/(|A|)=[{:(cos theta, sin theta),(-sin theta, cos theta):}]` |
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