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The mutual inductance between two adjacent coils is 1.5 H. If the current in the primary coil changes from 0 to 20 A in 0.05 s, determine the average emf induced in the secondary coil. If the number of turns in the secondary coil is 800, what change in flux will be observed in it? |
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Answer» The average value of induced emf, `e=-M(DeltaI)/(Deltat)=-1.5xx((20-0))/(0.05)=-(1.5xx20)/(0.05)=-600V` Hence, the magnitude of the induced emf = 600 V. Again, from the relation `phi=MI` we get, change in flux, `Deltaphi=M.DeltaI=1.5xx(20-0)=30Wb`. |
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