1.

The mutual inductance of the system of two coils is 5 mH. The current in the first coil varies according to the equation I = I_0sinomegat, where I_0 = 10 A and omega = 100pi"rad s"^(-1). The value of maximum induced emf in the second coil is ____

Answer»

`2piV`
`5piV`
`piV`
`4piV`

Solution :`epsilon=M.(dI)/(dt)` (NEGLECTING (-) SIGN),
`epsilon=M. d/(dt)` [ `I_0 sin omegat` ]
`therefore epsilon=M. I_0 omega cos omegat`
For maximum value , cos `omegat=1`
`therefore epsilon_"max"=MI_0 omega`
`=0.005xx10xx100pi`
`therefore epsilon=5piV`


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