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The net rate of reaction of the change : [Cu(NH_(3))_(4)]^(2+)+H_(2)O ?" "[Cu(NH_(3))_(3)H_(2)P]^(2+)+NH_(3) is, (dx)/(dt) =2.0xx10^(-4)[Cu(NH_(3))_(4)]^(2+)-3.0xx10^(5)[Cu(NH_(3))_(3)H_(2)O]^(2+)[NH_(3)] Calculate : the direction of reaction in which the abovereaction will be more predominant. |
| Answer» SOLUTION :More PREDOMINANT REACTION is BACKWARD reaction. | |