1.

The network shown in figure is a part of the circuit. (The battery has negligible resistance) At a certain instant the current I = 2A and it is decreasing at the rate of 10^2 "As"^(-1). What is the potential difference between the points B and A ?

Answer»

8.0 V
8.5 V
10 V
15 V

SOLUTION :`V_A-IR+epsilon-(-L(DI)/(dt))=V_B`
`THEREFORE V_B-V_A=-IR+ epsilon+L(dI)/(dt)`
`=-2xx2+12+5xx10^(-3)xx10^(-2)`
=-4+12+0.5
=8.5 V


Discussion

No Comment Found

Related InterviewSolutions