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The normal at the point `P(ap^2, 2ap)` meets the parabola `y^2= 4ax` again at `Q(aq^2, 2aq)` such that the lines joining the origin to P and Q are at right angle. Then (A) `p^2=2` (B) `q^2=2` (C) `p=2q`(D) `q=2p`A. `p^(2)+pq+2=0`B. `p^(2)-pq+2=0`C. `q^(2)+pq+2=0`D. `p^(2)+pq+1=0` |
| Answer» Correct Answer - A | |