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The normal component of the electric flux density is always discontinuous at the interface. State True/False.(a) True(b) FalseI had been asked this question in final exam.Origin of the question is Applications of Gauss Law topic in section Electrostatic Fields of Electromagnetic Theory

Answer» CORRECT choice is (a) True

The explanation is: In a dielectric-dielectric boundary, if a free surface CHARGE DENSITY exists at the interface, then the NORMAL components of the electric flux density are discontinuous at the boundary, which means Dn1 = Dn2.


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