1.

The normality of 10 lit. volume hydrogen peroxide is

Answer»

`0.176`
`3.52`
`1.78`
`0.88`

SOLUTION :`H_(2)O_(2)to H_(2)O+(1)/(2)O_(2)`
`1 M H_(2)O_(2)` solution = 2N = 34 gm/litre = 11.2
So Normality `=(2XX10)/(11.2)=17.8`


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