1.

The nuclear binding energy for Ar (39.962384 amu) is : (given mass of proton and neuron are 1.007825 amu and 1.008665amu respectively)

Answer»

<P>343.62 MEV
0.369096 MeV
931 MeV
None of these

Solution :`._(18)Ar^(40)`
Total no. of protons = 18
Total no. of neutrons = 22
Mass DEFECT `= [m xx p + m xx n] = 39.962384`
`= [1.007825 xx 18 + 1.008665 xx 22] - 39.962384`
`=[18.14085 + 22.19063] - 39.962384 = 0.369`
Binding ENERGY = mass defect `xx 931`
`= 0.369 xx 931 = 343.62 MeV`


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