1.

The nucleus is approximately spherical in shape. Then the surface area of nucleus haviing mass number A varies as.

Answer»

`A^(2//3)`
`A^(4//3)`
`A^(1//3)`
`A^(5//3)`

Solution :VOLUME of nucleus is PROPORTIONAL to MASS number
`4/3pi R^3 prop A , R =R_0 A^(1//3)`
So, `4piR^2=R_0A^(2//3) RARR 4piR^2 prop A^(2//3)`
SURFACE area is proportional to `"(mass number)"^(2//3)`


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