InterviewSolution
Saved Bookmarks
| 1. |
The nucleus of helium atom contains two protons that are separated by distance `3.0xx10^(-15)m`. The magnitude of the electrostatic force that each proton exerts on the other isA. 20.6 NB. 25.6 NC. 15.6 ND. 12.6 N |
|
Answer» Correct Answer - B Charge of proton is `q_(p)=1.6xx10^(-19)C` Distance between the protons is, `r=3xx10^(-15)m` The magnitude of electrostatic force between protons is `F_(e)=(q_(p)q_(p))/(4piepsilon_(0)r^(2))=(9xx10^(9)xx1.6xx10^(-19)xx1.6xx10^(-19))/((3xx10^(-15))^(2))=25.6N` |
|