Saved Bookmarks
| 1. |
The number densities of electrons and holes in pure Si at 27^(@)Cis 2xx10^(16)m^(-3). When it is doped with indium, the hole density increases to 4xx10^(22)m^(-3), find the electron density in doped sillicon. |
|
Answer» Solution :For extrinsic or doped semiconductor `n_(e).n_(h)=n_(i)^(2) RARR n_(e)=(n_(i)^(2))/(n_(h))` Here, `n_(i)=2XX10^(16)m^(-3) and n_(h)=4XX10^(22)m^(-3)` `rArr""n_(e)=((2xx10^(16)m^(-3))^(2))/(4xx10^(22)m^(-3))=10^(10)m^(-3)` |
|