The number density of free electrons in the semiconductor is 10^(18) m^(-3) . It is doped with a pentavalent impurity atoms of number density 10^(24) m^(-3) . The number density of free electrons m^(-3) increases by a factor of

The number density of free electrons in the semiconductor is 10^(18) m

1.	The number density of free electrons in the semiconductor is 10^(18) m^(-3) . It is doped with a pentavalent impurity atoms of number density 10^(24) m^(-3) . The number density of free electrons m^(-3) increases by a factor of
Answer» `4//3` 6 `10^6` `10^(24)` SOLUTION :number DENSITY of free electrons is `10^(18)+10^(24) ~=10^(24)` increase by factor `(10^(24))/10^(18)=10^6`.

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The number density of free electrons in the semiconductor is 10^(18) m^(-3) . It is doped with a pentavalent impurity atoms of number density 10^(24) m^(-3) . The number density of free electrons m^(-3) increases by a factor of

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