The number of 6 digits numbers that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by 11 and no digit is repeated isA. 60B. 72C. 48D. 36

The number of 6 digits numbers that can be formed using the digits 0,

1.	The number of 6 digits numbers that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by 11 and no digit is repeated isA. 60B. 72C. 48D. 36
Answer» Correct Answer - A Key idea Use divisibility test of 11 and consider different situation according to given condition. Since, the sum of given digits 0 + 1 + 2 + 5 + 7 + 9 = 24 Let the six - digit number be abcdef and to be divisible by 11, so the difference of sum of odd placed digits and sum of even placed digits should be either 0 or a multiple of 11 means `\| (a + c + e) - (b + d + f)\|` should be either 0 or a multiple of 11. Hence possible case is a + c + e = 12 = b + d + f (only) Now, Case I set {a, c, e} = {0, 5, 7} and set {b, d, f} = {1, 2, 9} So, number of 6 - digits number `= (2 xx 2!) xx (3!) = 24` [`because` a can be selected in ways only either 5 or 7]. Case II Set {a, c, e} = {1, 2, 9} and set {b, d, f} = {0, 5, 7} So, number of 6 - digits number `= 3! xx 3! = 36` So, total number of 6 - digits numbers = 24 + 36 = 60