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The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:(A) 27 (B) 18 (C) 81 (D) 512 |
Answer» The correct answer is D. Now, each of the 9 elements can be filled in two possible ways. Therefore, by the multiplication principle, the required number of possible matrices is 29 = 512 |
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