1.

The number of alpha and beta emitted in the nuclear reaction ""_(92)^(238)U to ""_(82)^(214)Pb is

Answer»

`8 beta`
`6 alpha`
`2 beta`
`5 alpha`

Solution :LET x `alpha- and y beta`- particle be emitted in the REACTION.
`""_(92)^(238)U to x ""_(2)^(4)alpha + y ""_(-1)^(0)beta + ""_(82)^(214)Pb`
Equating the MASS numbers on both sides,
`238 = 4x + y xx 0 + 214 implies 4x = 24 :.x= 6`
Equating atomic numbers on both sides,
`92 = 2x + (-y) + 82`
`92 = 2 xx 6 + (-y) + 82 implies - y = - 2 :. y = 2`
HENCE in the NUCLEAR reaction, `""_(92)^(238)U to ""_(82)^(214)Pb, 6 alpha`- and `2 beta` - particles are emitted.


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