1.

The number of alpha and beta-particles emitted in the nuclear reaction ._(90)Th^(228) rarr ._(83)Bi^(212) are respectively

Answer»

4 , 1
3 , 7
8, 1
4, 7

Solution :`._(90)Th^(228)rarr ._(83)Bi^(212)`
No. of `ALPHA-"particle" = (228 - 212)/(4) = (16)//(4) = 4`
No. of `BETA-"particle" = 2xx 4 - 90 + 83`


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