1.

The number of alpha- and beta-particles emitted when a radioactive element ._(90)E^(322) changes into ._(86)G^(220) will be

Answer»

5 and 4
2 and 3
3 and 2
4 and 1

Solution :`._(90)E^(232) rarr ._(86)G^(220)`
No. of `ALPHA " particle " = (232 - 220)/(4) = 3`
No. of `beta" particle " = 86 - [90 - 2 xx 3] = 2`


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