1.

The number of alpha particle in the nuclear reaction ""_(90)^(238) Th to ""_(81)^(212) Bi are : ____

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Solution :`""_(92) Th^(228) to ""_(83) Bi^(212) + a (""_(2)He^(4)) + b (""_(-1) beta^(0)) , a = ((228 - 212)/(4)) = (16)/(4) = 4 ALPHA , b = ?`


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