1.

The number of aluminium ions present in 54g of aluminium (atomic weight27) is

Answer»

2
18
`1.1 xx 10^(24)`
`1.2 xx 10^(24)`

SOLUTION :NUMBER of aluminium ions present in 54 G of aluminium
`= (6.203 xx 10^(23) xx 54)/(27) = 1.2 xx 10^(24)`


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