1.

The number of atoms in 0.1 mol of a triatomicgas is : (N_A = 6.02 xx 10^23 "mol"^(-1) )

Answer»

`3.600 XX 10^23`
`1.800 xx 10^22`
`6.02 xx 10^22`
`1.806 xx 10^23`

Solution :No. of MOLECULESIN 0.1 MOL` = 0.1 xx 6.02 xx 10^23`
No. of atoms ` = 0.1 xx 6.02 xx 10^23 xx 3`
` = 1.806 xx 10^23`


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