1.

The number of atoms in 0.1 mol triatomic gas is: (N_(A)=6.02xx10^(23)"mol"^(-1))

Answer»

`6.026xx10^(22)`
`1.806xx10^(23)`
`3.6xx10^(23)`
`1.8xx10^(22)`

SOLUTION :No. of ATOMS `=0.1xx3xx6.02xx10^(23)`
`=1.806xx10^(23)`


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