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| 1. |
The number of chloride ions which would be precipitated when the complex PtCl_(4).4NH_(3) is treated with silver nitrate is : (here coordination number of platinum is 6). |
| Answer» Solution :`[Pt(NH_(3))_(4)Cl_(2)]Cl_(2)rArr 2Cl^(-1) rArr 2 ` molesof AGCL ppt | |