The number of degrees of freedom for a mole of diatomic gas at N.T.P.

1.	The number of degrees of freedom for a mole of diatomic gas at N.T.P. is:
Answer» `30.1xx10^(23)` `18.01xx10^(23)` `30.1xx10^(21)` None of the above. Solution :At N.T.P. each molecule of diatomic gas POSSESSES 5 degress of FREEDOM i.e., f=5 1 mole of the gas contains `N=6.023xx10^(23)` molecules. `therefore` Total NUMBER of degress of freedom =Nf. `=6 CDOT 023xx10^(23)xx5=30cdot115xx10^(23)` Thus, correct choice is (a).

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The number of degrees of freedom for a mole of diatomic gas at N.T.P. is:

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