1.

the number of electric field lines leaving the positive 0.5 C charge placed in the medium of dielectric constant K = 10 are .......

Answer»

`5.65 xx 10^(9)`
`1.13 xx 10^(11)`
`9 xx 10^(9)`
`8.85 xx 10^(-12)`

SOLUTION :`rArr N=PHI` and `phi = Q/(Kepsilon_(0))`
`therefore phi = 0.5/(10 xx 8.85 xx 10^(-12))`
`=0.5649 xx 10^(10)`
`=5.65 xx 10^(9)`


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