1.

The number of electrons delivered at the cathode during electrolysis by a current of 1A in 60 seconds is (charge of electron = 1.6 xx 10^(-19) C)

Answer»

`6.22 xx 10^(23)`
`6.022 xx 10^(20)`
`3.75 xx 10^(20)`
`7.48 xx 10^(23)`

Solution :`Q = l t`
`= 1A = 60S`
96500 C CHARGE = `6.022 xx 10^(23) ` ELECTRONS
60 C charge = `(6.022 xx 10^(23))/(96500) xx 960 = 3.744 xx 10^(20)` electrons .


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