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The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)A. `6xx10^(23)`B. `6xx10^(20)`C. `3.75xx10^(20)`D. `7.48xx10^(23)` |
Answer» Correct Answer - C `Q=n e` `Ixxt=n e` `n=(1xx60)/(1.6xx10^(-19))` `n=3.75xx10^(20)` |
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