1.

The number of electrons passing per second through a cross section of copper wire carrying 10^(-6) aperes of current per second is found to be

Answer»

`1.6xx10^(-19)`
`6xx10^(-35)`
`6xx10^(-16)`
`6xx10^(12)`

Solution :Charge (coulombs) pass per second=`10^(-6)`
NUMBER of electrons passed per second
`=(10^(-6))/(1.602xx10^(-19))=6.24xx10^(12)`


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