1.

The number of electrons passing per second through a cross section of Cu wire carrying 10 ampere is

Answer»

`6 XX 10^(19)`
`8 xx 10^(19)`
` 1 xx 10^(19)`
`1.6 xx 10^(19)`

SOLUTION :CHARGE = `10 xx 1 = 10 C `
1 F = 96500 C = `6 xx 10^(23)` electron
`therefore` 10 C = n ELECTRONS
`therefore n = (6 xx 10^(23) xx 10)/(96500) = 6.2 xx 10^(19)`


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